F(1)=3x^2-5x+6

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Solution for F(1)=3x^2-5x+6 equation: 



(1)=3F^2-5F+6

We move all terms to the left:

(1)-(3F^2-5F+6)=0

We get rid of parentheses

-3F^2+5F-6+1=0

We add all the numbers together, and all the variables

-3F^2+5F-5=0

a = -3; b = 5; c = -5;
Δ = b2-4ac
Δ = 52-4·(-3)·(-5)
Δ = -35
Delta is less than zero, so there is no solution for the equation

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